C Program To Take Input of 5 Subject, Find Total And Calculate Percent

In this article, we are going to write a c program to Take Input of 5 Subject and find total and calculate percent. On the basis of percent provide grades like :

IF  Per > 80  “A+” 
Per >= 65 and per <=80  “A” 
Per > =50 and per <=65  “B” 
Per >= 42 and per <=50  “C” 
Per < 42  “Fail”

To make this program, we will use the following concept -:

• if else in c
• control statement in c

If you do not know about these topics well, then you may not understand this program, so you should know about them in detail from the link given above.

Now without wasting time let’s start programming.

Write a C Program To Take Input of 5 Subject, Find Total And Calculate Percent

Algorithm

• Start
• Declaration of variable
• Enter the subject marks
• Assign the value in variable
• Check condition
• Give answer according to condition
• Stop

Flowchart

Program

#include<stdio.h>
#include<conio.h>

void main()
{  
   int a,b,c,d,e,total;
   float per;

   printf("enter your marks");
   scanf("%d %d %d %d %d",&a,&b,&c,&d,&e);

   total=a+b+c+d+e;

   printf("\ntotal marks is %d\n",total);

   per=total*100/(5.0*100);

   printf("percent is %f\n",per);

   if(per>80)
    printf("A+");
   else{  if(per>=65&&per<=80)
             printf("A");
    else  { if(per>=50&&per <=65 )
                   printf("B");
      else {  if(per >= 42 && per <=50  )
                          printf("C");
       else
                 printf("Fail");
           }
       }
   }
  getch();
}

Output

Enter Your Marks 56 76 67 87 80

Total marks is 336
Percent is 73.199997
A

Read More

• Download C Language Notes Pdf
• C Language Tutorial For Beginners
• C Programming Examples With Output
• 250+ C Programs for Practice PDF Free Download

Conclusion

In this article, we have created all the following programs -:

• Write a C Program To Take Input of 5 Subject, Find Total And Calculate Percent

If you have difficulty to understand any program or have any doubts or questions, then tell me in the comment below.